When splitting your attack from a burst, every target gets the same defense penalty. I have gathered this because it doesn't specifically say you split the penalty up by the targets, and because burst defense penalties work on a similar system to the Shotgun rules, which does explicitly say that all targets in range of the spread take the same penalty.
I believe this is wrong. With this, executing Multiple Attack Burst-Fire with one weapon would be much better, than using Multiple Attacks while dual-wield same weapons. PC won't get any bonuses from dual-wielding and making two burst attacks over splitting one burst attack, exept doubling recoil penalty and doubling ammo expense (which aren'ta bonuses anyone seek for, lol). So, dual-wielding submachine guns, for example, is pretty much useless.
Dual-Wielding Burst-Fire will make sense when you split the penalties from autofire. I acccept that my reasons are more of groundless rationalization than of rule interpretation (and my Engrish is probably Ogrish :\), but still. I think that Burst-Fire rules don't work similar to Shotgun ones. When applying autofire penalties to target's Defence, you apply strictly same amount of penal dice, as number of bullets you fired (after the first). This is more clear when you look to Not Enough Bullets section. Accoring to this, I assume that PC must divide the amount of bullets fired in same manner as his Attack dice, and resolve this Multiple Attack as two (or more) Burst-Fire attacks with Not Enough Bullets.
If use this, Burst-Firing from two weapons (and making more shots) will actually make some sense.