Refer to our Texas Go Math Grade 6 Answer Key Pdf to score good marks in the exams. Test yourself by practicing the problems from Texas Go Math Grade 6 Module 6 Answer Key Multiplying and Dividing Integers.

## Texas Go Math Grade 6 Module 6 Answer Key Multiplying and Dividing Integers

**Texas Go Math Grade 6 Module 6 Are You Ready? Answer Key**

**Multiply.**

Question 1.

9 × 3 ______________

Answer:

9 × 3 = 27

When 9 is multiplied by an integer 1 through 9, digits of product add up to 9.

2 + 7 = 9

Question 2.

7 × 10 ______________

Answer:

7 × 10 = 70

Product of 10 and another integer ends in 0.

Question 3.

9 × 8 ______________

Answer:

9 × 8 = 72

When 9 is multiplied by an integer 1 through 9, digits of product add up to 9.

7 + 2 = 9

Question 4.

15 × 10 ______________

Answer:

15 × 10 = 150

Product of 10 and another integer ends in 0.

Question 5.

6 × 9 ______________

Answer:

6 × 9 = 54

When 9 is multiplied by an integer 1 through 9, digits of product add up to 9.

5 + 4 = 9

Question 6.

10 × 23 ______________

Answer:

10 × 23 = 230

Product of 10 and another integer ends in 0.

Question 7.

9 × 9 ______________

Answer:

9 × 9 = 81

When 9 is multiplied by an integer 1 through 9, digits of product add up to 9.

8 + 1 = 9

Question 8.

10 × 20 ______________

Answer:

10 × 20 = 200

Product of 10 and another integer ends in 0.

**Divide**

Question 9.

54 ÷ 9 ______________

Answer:

To calculate

54 ÷ 9

find the number that you need to multiply 9 times to get the value 54.

That number is 6:

6 × 9 = 54

Therefore,

54 ÷ 9 = 6

Question 10.

42 ÷ 6 ______________

Answer:

To calculate

42 ÷ 6

find the number that you need to multiply 6 times to get the value 42.

That number is 7:

7 × 6 = 42

Therefore,

42 ÷ 6 = 7

Question 11.

24 ÷ 3 ______________

Answer:

To calculate

24 ÷ 3

find the number that you need to multiply 3 times to get the value 24.

That number is 6:

8 × 3 = 24

Therefore,

24 ÷ 3 = 8

Question 12.

64 ÷ 8 ______________

Answer:

To calculate

64 ÷ 8

find the number that you need to multiply 8 times to get the value 64.

That number is 8:

8 × 8 = 64

Therefore,

64 ÷ 8 = 8

Question 13.

90 ÷ 10 ______________

Answer:

To calculate

90 ÷ 10

find the number that you need to multiply 10 times to get the value 90.

That number is 9:

9 × 10 = 90

Therefore,

90 ÷ 10 = 9

Question 14.

56 ÷ 7 ______________

Answer:

To calculate

56 ÷ 7

find the number that you need to multiply 7 times to get the value 56.

That number is 8:

8 × 7 = 56

Therefore,

56 ÷ 7 = 8

Question 15.

81 ÷ 9 ______________

Answer:

To calculate

81 ÷ 9

find the number that you need to multiply 9 times to get the value 81.

That number is 9:

9 × 9 = 81

Therefore,

81 ÷ 9 = 9

Question 16.

110 ÷ 11 ______________

Answer:

To calculate

110 ÷ 11

find the number that you need to multiply 11 times to get the value 110.

That number is 10:

10 × 11 = 110

Therefore,

110 ÷ 11 = 10

**Evaluate each expression.**

Question 17.

12 + 8 ÷ 2

Answer:

The expression you need to evaluate is:

12 + 8 ÷ 2

First divide integers from Left to right:

12 + 4

Then, add integers from Left to right:

12 + 4 = 16

Question 18.

15 – (4 + 3) × 2 ______________

Answer:

The expression you need to evaluate is:

15 – (4 + 3) × 2

First evaluate the expression in brackets:

15 – 7 × 2

Then, muLtipLy integers from Left to right:

15 – 14

At the end, subtract integers

15 – 14 = 1

Question 19.

18 – (8 – 5)^{2} _____________

Answer:

The expression you need to evaluate is:

18 – (8 – 5)^{2}

First evaluate the expression in brackets:

18 – 3^{2}

Then, find 3 to the power of 2

18 – 9

At the end, subtract integers

18 – 9 = 9

Question 20.

6 + 7 × 3 – 5 ______________

Answer:

The expression you need to evaluate is:

6 + 7 × 3 – 5

First multiply integers from left to right

6 + 21 – 5

At the end, add and subtract integers using ruLes for adding and subtracting integers:

6 + 21 – 5 = 22

Question 21.

9 + (2^{2} + 3^{2}) × 2 _____________

Answer:

The expression you need to evaluate is:

9 + (2^{2} + 3)^{2} × 2

First find 2 to the power of 2 to evaLuate the expression in brackets

9 + (4 + 3)^{2} × 2

9 + 7^{2} × 2

Find 7 to the power of 2:

9 + 49 × 2

Then, multiply integers from left to right

9 + 98

At the end, add integers

9 + 98 = 107

Result is 107

Evaluate the expression in brackets, find the value of that expression squared and then multiply and add integers from left to right.

Question 22.

6 + 5 – 4 × 3 ÷ 2 _____________

Answer:

The expression you need to evaluate is:

6 + 5 – 4 × 3 ÷ 2

First, multiply integers from left to right

6 + 5 – 12 ÷ 2

Then, divide integers from left to right

6 + 5 – 6

At the end, add and subtract integers from left to right:

11 – 6 = 5

Result is 5.

Multiply and divide integers from left to right and then add and subtract integers.

**Texas Go Math Grade 6 Module 4 Reading Start-Up Answer Key**

**Visualize Vocabulary
**

**Use the ✔ words to complete the chart. You may put more than one word in each box.**

**Understand Vocabulary**

**Complete the sentences using the review words.**

Question 1.

A ________________ is a number that ¡s less than 0. A ________________ is a number that is greater than 0.

Answer:

First requested review word is negative number

A negative number is less than 0 because it is left from 0 on the number line.

Second requested review word is positive number

A positive number is greater than 0 because it is right from 0 on the number line.

Question 2.

Division problems have three parts. The part you want to divide into groups is called the ________________. The number that is divided into another number is called the ________________. The answer to a division problem is called the ________________.

Answer:

First requested word is dividend

The dividend is a number that is being divided by another number

Second requested word is divisor

The divisor is a number that is contained in another number (the dividend).

Third requested word is quotient

The quotient is a number of equal parts into which the dividend has been divided by divisor

Question 3.

________________ are all whole numbers and their opposites.

Answer:

The requested word is integers

Integers are positive and negative numbers that can be written without fractional part.